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BCECE Medical BCECE Medical Solved Papers-2001

  • question_answer
    The element chlorine consists of a mixture of \[75.53%{{\,}_{17}}C{{l}^{35}}\] and \[24.47%{{\,}_{17}}C{{l}^{37}}\] having a mass of 34.97 amu and 36.95 amu, respectively. The atomic weight of chlorine is:

    A)  35.25          

    B)  35.45

    C)  36.25          

    D)  36.45

    Correct Answer: B

    Solution :

    Key Idea: At. wt. of chlorine \[=\frac{Abundance\,\,\times \,\,mass+Abundance\times mass}{100}\] Given, abundance of \[C{{l}^{35+}}\] isotope = 75.53% Mass of \[C{{l}^{35}}\] isotope = 34.97 Abundance of \[C{{l}^{37}}\] isotope = 24.47% Mass of \[C{{l}^{37}}\] isotope = 36.95 \[\therefore \] At. wt. of chlorine                 \[=\frac{34.97\times 75.53+24.47\times 36.95}{100}\]                 \[=\frac{3545.45}{100}\] = 35.45


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