A) \[{{3}^{o}}-\]nitroalkane
B) \[{{2}^{o}}-\]nitroalkane
C) \[{{1}^{o}}-\]nitroalkane
D) all of these
Correct Answer: A
Solution :
Key Idea: Tautomerism arises due to presence of labile hydrogen in organic compounds. The compounds haying a-hydrogen show tautomerism. \[\underset{{{1}^{o}}\text{ }nitroalkane}{\mathop{R-\overset{\begin{smallmatrix} H \\ |\alpha \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-N{{O}_{2}}}}\,\,\,\,\,\underset{{{2}^{o}}\text{ }nitroalkane}{\mathop{R-\overset{\begin{smallmatrix} R \\ |\alpha \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-N{{O}_{2}}}}\,\,\,\,\,\underset{{{3}^{o}}\text{ }nitroalkane}{\mathop{R-\overset{\begin{smallmatrix} R \\ |\alpha \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ R \end{smallmatrix}}{\mathop{C}}\,}}\,-N{{O}_{2}}}}\,\] \[\because \] \[{{3}^{o}}\] nitroalkane does not have any \[\alpha \]-hydrogen atom. \[\therefore \] \[{{3}^{o}}\] nitroalkane do not show tautomerism.
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