A) \[16\,g\,{{O}_{2}}\]
B) \[14\,g\,{{N}_{2}}\]
C) \[2\,g\,{{H}_{2}}\]
D) \[6\,g\,{{I}_{2}}\]
Correct Answer: C
Solution :
Key Idea: Molecular mass in gram\[=6.023\times {{10}^{23}}\] molecules [a] Molecular mass of oxygen = 32 g \[\therefore \] 32 g of \[{{O}_{2}}=6.023\times {{10}^{23}}\] molecules of \[{{O}_{2}}\] \[\therefore \] 16 g of \[{{O}_{2}}=0.5\times 6.023\times {{10}^{23}}\] molecules of \[{{O}_{2}}\] [b] Molecular mass of nitrogen = 28 g \[\therefore \] 28 g of \[{{N}_{2}}=6.023\times {{10}^{23}}\] molecules of \[{{N}_{2}}\] \[\therefore \] 14 g of \[{{N}_{2}}=0.5\times 6.023\times {{10}^{23}}\] molecules of \[{{N}_{2}}\] [c] Molecular mass of hydrogen = 2g \[\therefore \] 2 g of \[{{H}_{2}}=6.023\times {{10}^{23}}\] molecules of \[{{H}_{2}}\] [d] Molecular mass of iodine = 256 g \[\therefore \] 256 g of \[{{I}_{2}}=6.023\times {{10}^{23}}\] molecules of \[{{I}_{2}}\] \[\therefore \] 6 g of \[{{I}_{2}}=\frac{6}{256}\times 6.034\times {{10}^{23}}\] of \[{{I}_{2}}\] \[\therefore \] 2 g of \[{{H}_{2}}\] (choice c) has highest number of molecules.
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