A) \[dxy\]
B) \[dxz\]
C) \[d{{x}^{2}}-{{y}^{2}}\]
D) \[d{{z}^{2}}\]
Correct Answer: D
Solution :
The d orbital that participate in \[s{{p}^{3}}d\] hybridisation is \[{{d}_{z}}^{2}\].
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