BCECE Medical BCECE Medical Solved Papers-2002

  • question_answer
    Which is the correct electronic configuration of of Cr (chromium)?

    A)  \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{1}}3{{d}^{5}}\]

    B)  \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{2}}3{{d}^{4}}\]

    C)  \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{2}}3{{d}^{6}}\]

    D)  \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{1}}3{{d}^{8}}\]

    Correct Answer: A

    Solution :

    Key Idea: Exactly half filled orbitals are more stable than nearly half filled orbitals At no. of \[Cr=24\] \[=1{{s}^{2}}2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{1}},3{{d}^{5}}\]


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