BCECE Medical BCECE Medical Solved Papers-2002

  • question_answer
    On bombarding \[_{7}{{N}^{14}}\] with \[\alpha \]-particles, the nuclei of the product formed after the release of a proton is :

    A)  \[_{8}{{O}^{17}}\]

    B)  \[_{8}{{O}^{18}}\]

    C)  \[_{9}{{F}^{7}}\]

    D)  \[_{9}{{F}^{18}}\]

    Correct Answer: A

    Solution :

    Key Idea: (i) Sum of atomic numbers of reactants = Sum of atomic numbers of products. (ii) Sum of atomic masses of reactants = Sum of atomic masses of products. \[\underset{nitrogen}{\mathop{_{7}{{N}^{14}}}}\,+\,\,\underset{\alpha -particle}{\mathop{_{2}H{{e}^{4}}}}\,\xrightarrow{{}}\,\,\underset{oxygen}{\mathop{_{8}{{O}^{17}}}}\,+\,\,\underset{proton}{\mathop{_{1}{{H}^{1}}}}\,\]


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