A) +6
B) +4
C) +2
D) +3
Correct Answer: A
Solution :
Key Idea: The sum of oxidation states of all elements in a compound is always zero. Let oxidation state of S in \[{{H}_{2}}S{{O}_{4}}=x\] \[\therefore \] \[(+1\times 2)+x+(-2\times 4)=0\] or \[x+2-8=0\] \[\therefore \] \[x=+6\]
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