A) \[C{{H}_{3}}C{{H}_{2}}COOH\]
B) \[C{{H}_{3}}CHOHCOOH\]
C) \[HOOC\,.\,C{{H}_{2}}\,.\,COOH\]
D) \[C{{H}_{3}}\,.\,\,CO\,.\,COOH\]
Correct Answer: B
Solution :
Key Idea: Optically active compound has at least one asymmetric or chiral carbon atom [a] \[C{{H}_{3}}-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-COOH\] [b] \[C{{H}_{3}}{{-}^{*}}\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ COOH \end{smallmatrix}}{\mathop{C}}\,}}\,-COOH\] [c] \[COOH-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-COOH\] [d] \[C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-COOH\] Only choice [b] has asymmetric carbon atom (marked *) So it is optically active
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