BCECE Medical BCECE Medical Solved Papers-2003

  • question_answer
    The pressure and density of a diatomic gas \[\left( \gamma =\frac{7}{5} \right)\] change adiabatically from (P, d) to (P, d). If \[\frac{d}{d}=32\], then \[\frac{p}{p}\] should be :

    A)  \[\frac{1}{128}\]

    B)  32

    C)  128           

    D)  none of these

    Correct Answer: C

    Solution :

    In an adiabatic process \[P{{V}^{\gamma }}=\] constant Now, volume \[=\frac{mass}{density}\] i.e., \[V=\frac{M}{d}\] \[\therefore \] \[P{{\left[ \frac{M}{d} \right]}^{\gamma }}=\] constant or \[\frac{P}{{{d}^{\gamma }}}=a\], new constant, or \[\frac{P}{{{d}^{\gamma }}}=\frac{P}{{{d}^{\gamma }}}\] or \[\frac{P}{P}={{\left( \frac{P}{d} \right)}^{\gamma }}\] but \[\frac{P}{d}=32\] and \[\gamma =\frac{7}{5}\] \[\therefore \] \[\frac{P}{P}={{(327)}^{7/5}}={{\left[ {{(3\,2)}^{1/5}} \right]}^{7}}\] \[={{2}^{7}}\] = 128


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