A) \[\frac{\pi }{2}\]
B) \[\frac{\pi }{4}\]
C) zero
D) nothing can be said
Correct Answer: C
Solution :
In a series LCR circuit, potential difference leads the current by an angle \[\phi \] (let). \[\phi ={{\tan }^{-1}}\left( \frac{{{X}_{L}}-{{X}_{C}}}{R} \right)\] or \[\phi ={{\tan }^{-1}}\left( \frac{\omega L-\frac{1}{\omega C}}{R} \right)\] At resonance, \[{{X}_{L}}={{X}_{C}},\,i.e.,\,\,\omega L=\frac{1}{\omega C}\] Hence, \[\phi ={{\tan }^{-1}}(0)=0\] Therefore, phase difference between current and voltage at resonance is zero.
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