question_answer

A soap bubble in vacuum has a radius 3 cm and another soap bubble in vacuum has radius 4 cm. If two bubbles coalesce under isothermal condition, then the radius of the new bubble will be :

A)  7 cm          

B)  5 cm 

C)  4.5 cm        

D)  2.3 cm

Correct Answer: B

Solution :

Key Idea: An isothermal process obeys Boyles law. Since, process is isothermal the total a pressure of air inside bubble is same as excess of pressure given by where T is surface tension and R is radius. Also, an isothermal process obeys Boyles law. Hence, PV= constant. Let R be the radius of coalesce system, then \[{{P}_{1}}{{V}_{1}}+{{P}_{2}}{{V}_{2}}=PV\]                         \[\left( \frac{4T}{{{R}_{1}}} \right)\left( \frac{4}{3}\pi R_{1}^{3} \right)+\left( \frac{4T}{{{R}_{2}}} \right)\left( \frac{4}{3}\pi R_{2}^{3} \right)=\left( \frac{4T}{R} \right)\left( \frac{4}{3}\pi {{R}^{3}} \right)\] \[\Rightarrow \] \[r_{1}^{2}+r_{2}^{2}={{R}^{2}}\] Given, \[{{R}_{1}}=3\,\,cm,\,\,{{R}_{2}}=4\,\,cm\] \[\therefore \] \[R=\sqrt{{{3}^{2}}+{{4}^{2}}}\] \[\Rightarrow \] \[R=5\,\,cm\]