A) \[C{{H}_{2}}Br-CH=C{{H}_{2}}\]
B) \[C{{H}_{2}}-\overset{\begin{smallmatrix} Br \\ | \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}\]
C) \[C{{H}_{3}}CH=CHBr\]
D) none of the above
Correct Answer: A
Solution :
Key Idea: The reaction is called allylic substitution.
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