BCECE Medical BCECE Medical Solved Papers-2003

  • question_answer
    The amount of substance that gives \[3.7\times {{10}^{7}}\]dps, is :

    A)  one becquerel  

    B)  one curie

    C)  one millicurie  

    D)  one Rutherford

    Correct Answer: C

    Solution :

    Key Idea: One curie is the amount of radio active element which gives \[3.7\times {{10}^{10}}\]disintegration per second. \[\therefore \] 1 millicurie \[=3.7\times {{10}^{7}}\] dps.


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