A) \[n=5,\,l=0,\,\,m=0,\,\,s=+1/2\]
B) \[n=5,\,l=1,\,\,m=1,\,\,s=+1/2\]
C) \[n=5,\,l=1,\,\,m=1,\,\,s=+1/2\]
D) \[n=6,\,l=0,\,\,m=0,\,\,s=+1/2\]
Correct Answer: A
Solution :
Key Idea : Write configuration o/Rb and then find quantum numbers of valence electron. Rb- Atomic number is 3 7, so configuration is \[1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{2}},3{{d}^{10}},4{{p}^{6}},5{{s}^{1}}\] \[\therefore \] Last electron (valence electron) is \[5{{s}^{1}}\] \[\therefore \] \[n=5\] (\[\because \] electron enters 5 energy level) \[l=0\] (\[\because \] kiss sub-shell). \[m=0\] \[s=1/2\]
You need to login to perform this action.
You will be redirected in
3 sec
