A) \[{{127}^{o}}C\]
B) \[{{227}^{o}}C\]
C) \[{{327}^{o}}C\]
D) \[{{673}^{o}}C\]
Correct Answer: B
Solution :
Efficiency of heat engine is given by \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] where \[{{T}_{1}}\] is the temperature of source and \[{{T}_{2}}\]is the temperature of sink. Given, \[\eta =\frac{30}{100}=0.3\], \[{{T}_{2}}=277+273=350\,\,K,\,{{T}_{1}}=?\] Substituting values in the relation, we have \[0.3=1-\frac{350}{{{T}_{1}}}\] or \[\frac{350}{{{T}_{1}}}=0.3=0.7\] \[\therefore \] \[{{T}_{1}}=\frac{350}{0.7}=500\,K={{227}^{o}}C\]
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