BCECE Medical BCECE Medical Solved Papers-2004

  • question_answer
    The resistance of a bulb filament is 100 0 at temperature of \[{{100}^{o}}C\]. If its temperature coefficient of resistance be \[0.005{{/}^{o}}C\], its resistance will become 200\[\Omega \] at a temperature of:

    A) \[{{300}^{o}}C\]

    B) \[{{400}^{o}}C\]

    C)  \[{{500}^{o}}C\]

    D)  \[{{200}^{o}}C\]

    Correct Answer: B

    Solution :

    Let resistance of bulb filament is \[{{R}_{0}}\]at \[{{0}^{o}}C\]then from expression                 \[R={{R}_{0}}\,[1+\alpha \,\Delta \theta ]\] we have, \[100={{R}_{0}}[1+0.005\times 100]\] and        \[200={{R}_{0}}[1+0.005\times x]\] where \[x\] is temperature in \[^{o}C\] at which resistance becomes \[200\,\,\Omega \]. Dividing the above two equations, we have                 \[\frac{200}{100}=\frac{1+0.005x}{1+0.005\times 100}\] \[\Rightarrow \] \[x={{400}^{o}}C\]


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