A) \[{{H}_{2}}{{S}_{2}}{{O}_{4}}\]
B) \[{{H}_{2}}{{S}_{2}}{{O}_{6}}\]
C) \[{{H}_{2}}{{S}_{2}}{{O}_{8}}\]
D) none of these
Correct Answer: C
Solution :
Key Idea: Draw structure of all compounds to find which of them does not have \[S-S\] bond. \[\underset{hyposulphurous\text{ }acid}{\mathop{\underset{\underset{(a)}{\mathop{{{H}_{2}}{{S}_{2}}{{O}_{4}}}}\,}{\mathop{H-O-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}\,-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}\,-O-H}}\,}}\,\] \[\underset{\begin{smallmatrix} {{H}_{2}}{{S}_{2}}{{O}_{6}} \\ (b) \\ dithionic\text{ }acid \end{smallmatrix}}{\mathop{H-O-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{S}}\,}}\,-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{S}}\,}}\,-O-H}}\,\] \[\underset{\begin{smallmatrix} {{H}_{2}}{{S}_{2}}{{O}_{8}} \\ (c) \\ Marshalls\text{ }acid \end{smallmatrix}}{\mathop{H-O-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{S}}\,}}\,-O-O-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{S}}\,}}\,-O-H}}\,\] \[\therefore \] Marshalls acid does not have \[S-S\] bond.
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