A) \[{{H}_{2}}C=\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,-CH=C{{H}_{2}}\]
B) \[{{H}_{2}}C=\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{C}}\,-CH=C{{H}_{2}}\]
C) \[\overset{\begin{smallmatrix} {{C}_{6}}{{H}_{5}} \\ | \end{smallmatrix}}{\mathop{C}}\,H=C{{H}_{2}}\]
D) \[-{{(C{{H}_{2}}-C{{H}_{2}})}_{n}}-\]
Correct Answer: A
Solution :
[a] \[{{H}_{2}}C=\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,-CH=C{{H}_{2}}\] is isoprene or 2-methyl 1,3-butadiene. It is monomer of natural rubber [b] \[{{H}_{2}}C=\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{C}}\,-CH=C{{H}_{2}}\] is chloroprene or 2 -chloro 1,3-butadiene is monomer of neoprene. [c] \[{{C}_{6}}{{H}_{5}}CH=C{{H}_{2}}\] is styrene. It is copolymer of buna-S rubber [d] \[-{{(C{{H}_{2}}-C{{H}_{2}})}_{n}}-\]- is polythene \[\therefore \] [a] is correct answer.
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