A) \[C{{H}_{3}}OH\]
B) \[{{C}_{2}}{{H}_{5}}OH\]
C) \[C{{H}_{2}}C{{H}_{2}}COOH\]
D) \[{{(C{{H}_{3}})}_{2}}CHOH\]
Correct Answer: A
Solution :
Key Idea: Methyl alcohol \[(C{{H}_{3}}OH)\] is prepared bypass \[{{H}_{2}}\] in water gas in presence of catalyst \[\underset{water}{\mathop{Co+{{H}_{2}}}}\,+{{H}_{2}}\xrightarrow[300-{{400}^{o}}C]{C{{r}_{2}}{{O}_{3}}-ZnO}\underset{methyl\text{ }alcohol}{\mathop{C{{H}_{3}}OH}}\,\]
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