A) \[Fe{{(OH)}_{3}}\]
B) \[Zn{{(OH)}_{2}}\]
C) \[Al{{(OH)}_{3}}\]
D) \[Sn{{(OH)}_{2}}\]
Correct Answer: A
Solution :
Key Idea: \[Fe{{(OH)}_{3}}\] is not soluble in \[NaOH\] [b] \[Zn{{(OH)}_{2}}+NaOH\xrightarrow{{}}\underset{\begin{smallmatrix} sod.\text{ }zincate \\ (soluble) \end{smallmatrix}}{\mathop{N{{a}_{2}}Zn{{O}_{2}}}}\,\,+2{{H}_{2}}O\] [c] \[Al{{(OH)}_{3}}+NaOH\xrightarrow{{}}\underset{\begin{smallmatrix} sod.\text{ }aluminate \\ (soluble) \end{smallmatrix}}{\mathop{NaAl{{O}_{2}}}}\,\,+2{{H}_{2}}O\] [d] \[Sn{{(OH)}_{2}}+NaOH\xrightarrow{{}}\underset{\begin{smallmatrix} sod.\text{ }stannate \\ (soluble) \end{smallmatrix}}{\mathop{N{{a}_{2}}Sn{{O}_{2}}}}\,\,+2{{H}_{2}}O\]
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