A) 5 erg
B) 5 J
C) 0.5 erg
D) 0.5 J
Correct Answer: D
Solution :
Work done by force F in stretching the wire through distance x is, \[W=\frac{1}{2}\,Fx\] Given, \[F=1\,kN=1000\,N\], \[x=1\,mm=1\times {{10}^{-3}}m\] \[\therefore \] \[W=\frac{1}{2}\times 1000\times 1\times {{10}^{-3}}=0.5\,J\]
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