BCECE Medical BCECE Medical Solved Papers-2005

  • question_answer
    The figure shows a network of currents. The magnitude of current is shown here The current/will be:

    A)  3 A           

    B)  9 A

    C)  13 A         

    D)  19 A

    Correct Answer: C

    Solution :

    Regarding Kirchhoffs junction rule, the circuit can be redrawn as : Current in arm, AB = 10 - 6 = 4A Current in arm, DC = 6 + 2 = 8A Current in arm, BC = 4 + 1 = 5A Hence, \[J=5+8=13\,A\]


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