A) 7
B) 6
C) 5
D) 4
Correct Answer: A
Solution :
Key Idea: \[\alpha \]-particle is a nucleus of helium atom and its symbol is \[_{2}H{{e}^{4}}\]. When an \[\alpha \]-particle is emitted from a nucleus, the resultant nucleus reduces in mass number by 4 unit and in atomic number by 2 unit. Loss in mass number = 232 - 204 = 28 Therefore, number of \[\alpha \]-particles emitted \[=\frac{28}{4}\] = 7
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