BCECE Medical BCECE Medical Solved Papers-2005

  • question_answer
    Oxidation number of S in \[SO_{4}^{2-}\]:

    A)  +6           

    B)  +3

    C)  +2          

    D)  -2

    Correct Answer: A

    Solution :

    Key Idea: The sum of oxidation states of all elements in an ion is equal to charge on it. Let the oxidation state of S in \[SO_{4}^{2-}=x\] \[\therefore \] \[x+(-2\times 4)=-2\] or \[x=+6\]


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