A) \[{{C}_{2}}{{H}_{6}}\]
B) \[C{{H}_{4}}\]
C) \[{{C}_{2}}{{H}_{4}}\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: C
Solution :
Key Idea: (i) Alkene and alkynes both react with \[KMn{{O}_{4}}\] and decolorise it (ii) Only alkynes react with \[AgN{{O}_{3}}\] to give while precipitate. \[\underset{\begin{smallmatrix} {{C}_{2}}{{H}_{6}} \\ \,(a) \\ alkane \end{smallmatrix}}{\mathop{H-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-H}}\,\] \[\underset{\begin{smallmatrix} C{{H}_{4}} \\ \,(b) \\ alkane \end{smallmatrix}}{\mathop{H-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-H}}\,\] \[\underset{\begin{smallmatrix} {{C}_{2}}{{H}_{4}} \\ \,(c) \\ alkene \end{smallmatrix}}{\mathop{H-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}\,=\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}\,-H}}\,\] \[\underset{\begin{smallmatrix} {{C}_{2}}{{H}_{2}} \\ \,(d) \\ alkyne \end{smallmatrix}}{\mathop{H-C\equiv C-H}}\,\] \[\therefore \] \[{{C}_{2}}{{H}_{4}}\] (an alkene) reacts with \[KMn{{O}_{4}}\] and decolorises it and does not react with . \[AgN{{O}_{3}},\,{{C}_{2}}{{H}_{6}}\] and \[C{{H}_{4}}\] are alkane they do not react with \[KMn{{O}_{4}}\] and \[AgN{{O}_{3}}\].
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