A) \[H-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{P}}\,}}\,-OH\]
B) \[HO-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{P}}\,}}\,-OH\]
C) \[H-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{P}}\,}}\,=OH\]
D) \[H-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{P}}\,}}\,-OH\]
Correct Answer: A
Solution :
Hypophosphorus acid is \[{{H}_{3}}P{{O}_{4}}\]
It is monobasic acid.
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