A) 6 \[V{{m}^{-1}}\]
B) 60 \[V{{m}^{-1}}\]
C) \[\frac{1}{6}\,\,V{{m}^{-1}}\]
D) none of these
Correct Answer: B
Solution :
We can write the electric and magnetic fields as sinusoidal functions of position x and time t. \[E={{E}_{0}}\sin \,\,(kx-\omega \,t)\] \[B={{B}_{0}}\sin \,\,(kx-\omega \,t)\] In this \[{{E}_{0}}\] and \[{{B}_{0}}\] are the amplitudes of the fields. Further \[c=\frac{{{E}_{0}}}{{{B}_{0}}}\] or \[{{E}_{0}}={{B}_{{{0}^{C}}}}\] Given, \[{{B}_{0}}=2\times {{10}^{-7}}\times 3\times {{10}^{8}}=60\,\,V{{m}^{-1}}\] we have \[{{E}_{0}}=2\times {{10}^{-7}}\times 3\times {{10}^{8}}=60\,\,V{{m}^{-1}}\]
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