A) \[KCl{{O}_{4}}\]
B) \[KCl{{O}_{3}}\]
C) \[KCl{{O}_{2}}\]
D) \[KClO\]
Correct Answer: B
Solution :
When chlorine is passed into hot concentrated solution of KOH, potassium chlorate is formed. \[6KOH+3C{{l}_{2}}\underset{potassium\text{ }chlorate}{\mathop{\xrightarrow{{}}5KCl+KCl{{O}_{3}}+3{{H}_{2}}O}}\,\]
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