question_answer

In the equation\[{{H}_{2}}S+2HN{{O}_{3}}\xrightarrow{{}}2{{H}_{2}}O+2N{{O}_{2}}+S\]. The equivalent weight of hydrogen sulphide is :

A)  18             

B)  68

C)  34     

D)  17

Correct Answer: D

Solution :

\[{{H}_{2}}S+2HN{{O}_{3}}\xrightarrow{{}}2{{H}_{2}}O+2N{{O}_{2}}+S\] Hence, the equivalent weight of \[{{H}_{2}}S=\frac{molecular\text{ }weight}{change\text{ }in\text{ }oxidation\text{ }number}=\frac{34}{2}=17\]