A) \[{{325}^{o}}C\]
B) 325 K
C) \[{{39}^{o}}C\]
D) \[{{320}^{o}}C\]
Correct Answer: C
Solution :
For a refrigerator coefficient of performance (COP) is defined as the ratio of the amount of heat removed at the lower temperature to the work put into the system (i. e., the engine) \[COP=\frac{{{Q}_{low}}}{W}=\frac{{{T}_{low}}}{{{T}_{high}}-{{T}_{low}}}\] Given, \[{{T}_{low}}=273-13=260\,K,\,COP=5\] \[\Rightarrow \] \[5=\frac{260}{{{T}_{H}}-260}\] \[\Rightarrow \] \[5{{T}_{H}}=-1300=260\] \[\Rightarrow \] \[{{T}_{H}}=312\,K\] \[\Rightarrow \] \[{{T}_{H}}=312-273={{39}^{o}}C\]
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