question_answer

In the given figure the steady state current in the circuit i&

A)  zero            

B)  0.6 A

C)  0.9 A           

D)  1.5 A

Correct Answer: D

Solution :

Key Idea: In the steady state there is no current in the capacitor branch. In the given circuit the resistors of\[2\Omega \] and\[3\Omega \]are connected in parallel hence, equivalent resistance is                 \[\frac{1}{R}=\frac{1}{2}+\frac{1}{3}=\frac{5}{6}\] \[\therefore \]  \[R=\frac{6}{5}\Omega \] Also in steady state, the circuit is shown as. Resistors of \[\frac{6}{5}\Omega \] and \[2.8\,\Omega \] are connected in series Hence,  \[R\,\,=\frac{6}{5}\Omega +2.8\,\Omega \]                 \[=1.2\Omega +2.8\Omega \]                 \[=4.0\,\Omega \] From Ohms law, Current \[i=\frac{V}{R}=\frac{6}{4.0}=1.5\,A\]