A) \[3.125\times {{10}^{13}}\]
B) \[6.25\times {{10}^{13}}\]
C) \[1.525\times {{10}^{13}}\]
D) None of these
Correct Answer: A
Solution :
We know that \[1\,kW=1\times {{10}^{3}}J/s\] Also. \[1.6\times {{10}^{-19}}J=1\,\,eV\] \[\therefore \]\[200\,\,MeV=200\times 1.6\times {{10}^{-19}}\times {{10}^{6}}J\] Number of fissions \[=\frac{Power}{Energy\text{ }released}\] \[=\frac{{{10}^{3}}}{200\times 1.6\times {{10}^{-13}}}\] \[=3.125\times {{10}^{13}}\].
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