A) \[{{C}_{6}}{{H}_{5}}-N=N-{{C}_{6}}{{H}_{5}}\]
B) \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\]
C) \[{{C}_{6}}{{H}_{5}}NO\]
D) \[{{C}_{6}}{{H}_{6}}NHOH\]
Correct Answer: D
Solution :
Key Idea: When nitrobenzene is reduced with a neutral reducing agent (Zn dust -\[N{{H}_{4}}Cl,\,Al-Hg\] couple and water etc), phenylhydroxylamine is formed. \[{{C}_{6}}{{H}_{5}}N{{O}_{2}}+2[H]\xrightarrow[+N{{H}_{4}}Cl-{{H}_{2}}O]{Zn\,\,dust}\] \[\underset{Nitrosobenzene}{\mathop{{{C}_{6}}{{H}_{5}}NO}}\,\,\,\xrightarrow{2[H]}\underset{\begin{smallmatrix} Phenyl\text{ }hydroxyl \\ amine \end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{5}}NHOH}}\,\]
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