A) time
B) mass
C) length
D) force
Correct Answer: A
Solution :
Dimensions of \[E=[M{{L}^{2}}{{T}^{-2}}]\] Dimensions of \[G=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\] Dimensions of \[I=[ML{{T}^{-1}}]\] and dimensions of \[M=[M]\] So, dimensions of-;,- \[\frac{[G]\,\,[I]\,\,[{{M}^{2}}]}{[{{E}^{2}}]}\] Substituting the dimensions for each physical quantity, we get Dimensions of \[\frac{GI{{M}^{2}}}{{{E}^{2}}}\] \[=\frac{[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\,\,[ML{{T}^{-1}}]\,\,[{{M}^{2}}]}{{{[M{{L}^{2}}{{T}^{-2}}]}^{2}}}\] = [T] = Dimensions of time
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