A) \[1\times {{10}^{-9}}M\,HCl\] solution
B) \[1\times {{10}^{-5}}M\,NaOH\] solution
C) \[1\times {{10}^{-9}}M\,KOH\] solution
D) Both [a] and [b]
Correct Answer: B
Solution :
[a] pH of \[{{10}^{-9}}\] M HCl will be < 7 [b] pOH of \[{{10}^{-5}}NaOH=-\log \,\,[O{{H}^{-}}]\] \[=-\log \,\,[1\times {{10}^{-5}}]\] = 5 \[pH+pOH=14\] \[pH=14-5=9\] [c] pH of \[{{10}^{-9}}\] M KOH will be slightly greater than 7.
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