A) increase by 1%
B) decrease by 1%
C) increase by 2%
D) decrease by 2%
Correct Answer: C
Solution :
Power \[p={{I}^{2}}R\] \[\therefore \] \[p\propto {{I}^{2}}\] Then \[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{{{I}^{2}}}{{{\left( \frac{101}{100} \right)}^{2}}{{I}^{2}}}\] Percentage increase in power \[\left( \frac{{{p}_{2}}}{{{p}_{1}}}-1 \right)%=\left( \frac{101\times 101}{100\times 100}-1 \right)%\] = 2%
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