A) 2.5 \[km{{s}^{-1}}\]
B) 10 \[km{{s}^{-1}}\]
C) 5 kms
D) 20 \[km{{s}^{-1}}\]
Correct Answer: C
Solution :
The spectral shift \[(z)=\frac{\lambda -{{\lambda }_{0}}}{{{\lambda }_{0}}}\] Also, \[z=\frac{Velocity\text{ }of\,recession\text{ }of\text{ }star\text{ (}v)}{Velocity\text{ }of\text{ }light\text{ (c)}}\] \[\therefore \] \[v=\frac{\lambda -{{\lambda }_{0}}}{{{\lambda }_{0}}}\times c\] \[=\frac{0.1}{6000}\times 3\times {{10}^{8}}=5000\,m{{s}^{-1}}\] = 5 km \[{{s}^{-1}}\]
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