A) CE
B) \[\frac{CE{{R}_{1}}}{{{R}_{1}}+r}\]
C) \[\frac{CE{{R}_{2}}}{{{R}_{2}}+r}\]
D) \[\frac{CE{{R}_{1}}}{{{R}_{2}}+r}\]
Correct Answer: B
Solution :
\[{{R}_{total}}={{R}_{1}}+r\] (Since capacitor is a DC blocking element) \[V=i{{R}_{1}}\] \[V=\frac{E{{R}_{1}}}{{{R}_{1}}+r}\] \[\left( \because i=\frac{E}{{{R}_{1}}+r} \right)\] Since, \[q=CV\] \[\Rightarrow \] \[q=\frac{CE{{R}_{1}}}{{{R}_{1}}+r}\]
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