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BCECE Medical BCECE Medical Solved Papers-2010

  • question_answer
    The potential difference in volt across the resistance ^3 in the circuit shown in figure, is \[({{R}_{1}}=15\,\,\Omega ,{{R}_{2}}=15\,\Omega ,\,{{R}_{3}}=30\,\Omega ,\,{{R}_{4}}=35\,\Omega )\]

    A)  5                

    B)  7.5

    C)  15               

    D)  12.5

    Correct Answer: C

    Solution :

    Total resistance of the circuit                 \[R+\frac{({{R}_{1}}+{{R}_{2}})\times {{R}_{3}}}{({{R}_{1}}+{{R}_{2}})+{{R}_{3}}}\]                 \[=35+\frac{(15+15)\times 30}{(15+15)+30}\]                 \[=35+\frac{30\times 30}{30+30}=50\,\,\Omega \] Current in circuit, \[i=\frac{50}{50}=1\,A\] Current through \[{{R}_{3}},\,i={{i}_{2}}=\frac{1}{2}A\]                 Potential difference across \[{{R}_{3}}\] \[=i\times {{R}_{3}}=\frac{1}{2}\times 30=15\,\,V\]


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