A) 0.12 \[Wb/{{m}^{2}}\]
B) 1.2 \[Wb/{{m}^{2}}\]
C) 12 \[Wb/{{m}^{2}}\]
D) 120 \[Wb/{{m}^{2}}\]
Correct Answer: C
Solution :
Magnetic field produced at the centre \[B=\frac{{{\mu }_{0}}i}{2\,r}\] \[=\frac{{{\mu }_{0}}}{2\,r}\frac{q}{T}=\frac{{{\mu }_{0}}}{2\,r}ef\] \[\therefore \] \[B=\frac{4\pi \times {{10}^{-7}}}{2\times 0.53\times {{10}^{-10}}}\times 1.6\times {{10}^{-19}}\] \[\times 6.6\times {{10}^{15}}\] \[=\frac{2\pi }{0.53}\times 1.6\times 6.6\times {{10}^{-1}}\] \[\approx 12\,Wb/{{m}^{2}}\]
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