A) \[1.6\times {{10}^{-21}}c{{m}^{3}}\]
B) \[2.81\times {{10}^{-23}}c{{m}^{3}}\]
C) \[6.02\times {{10}^{-23}}c{{m}^{3}}\]
D) \[6.6\times {{10}^{-24}}c{{m}^{3}}\]
Correct Answer: B
Solution :
Volume of the unit cell \[={{a}^{3}}\] \[=\,{{(3.04\times {{10}^{-10}})}^{3}}\] \[=\,2.81\times {{10}^{-29}}{{m}^{3}}\] \[=\,2.81\times {{10}^{-23}}c{{m}^{3}}\]
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