A) \[\frac{E}{V}=\frac{p}{2}\]
B) \[\frac{E}{V}=\frac{1}{3}p\]
C) \[\frac{E}{V}=\frac{2}{3}p\]
D) \[\frac{E}{V}=\frac{3}{2}p\]
Correct Answer: D
Solution :
Pressure \[p=\frac{1}{2}\frac{m{{\overline{c}}^{2}}}{V}\] \[\frac{1}{2}m{{\overline{c}}^{2}}=\frac{3}{2}pV\] \[E=\frac{3}{2}pV\] \[\frac{E}{V}=\frac{3}{2}p\]
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