A) \[0.16\times {{10}^{-6}}m,\,\,6.25\times {{10}^{14}}Hz\]
B) \[0.36\times {{10}^{-6}}m,\,\,6.25\times {{10}^{14}}Hz\]
C) \[0.36\times {{10}^{-6}}m,\,\,3.25\times {{10}^{14}}Hz\]
D) \[0.26\times {{10}^{-6}}m,\,\,6.25\times {{10}^{14}}Hz\]
Correct Answer: B
Solution :
\[{{\lambda }_{m}}=\frac{{{\lambda }_{a}}}{\mu }=\frac{0.48\times {{10}^{-6}}}{4/3}m=0.36\times {{10}^{-6}}\,\,m\] Frequency of light in air \[v=\frac{c}{{{\lambda }_{a}}}=\frac{3\times {{10}^{8}}}{0.48\times {{10}^{-6}}}=6.25\times {{10}^{14}}Hz\] On passing through water (medium), frequency does not change. Hence, it will be\[6.25\times {{10}^{14}}Hz\] in water.
You need to login to perform this action.
You will be redirected in
3 sec
