BCECE Medical BCECE Medical Solved Papers-2011

  • question_answer
    A radio transmitter operates at a frequency of 880 kHz and power of 10 kW. The number of photons emitted per second is

    A)  \[13.27\times {{10}^{4}}\]     

    B)  \[13.27\times {{10}^{34}}\]

    C)  \[1327\times {{10}^{34}}\]

    D)  \[1.71\times {{10}^{31}}\]

    Correct Answer: D

    Solution :

    Number of photons emitted per second                 \[=\frac{Power}{hv}=\frac{10\times {{10}^{3}}}{6.6\times {{10}^{-34}}\times 880\times {{10}^{3}}}\] \[=1.71\times {{10}^{31}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner