BCECE Medical BCECE Medical Solved Papers-2011

  • question_answer
    Given, C (diamond) \[+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}};\Delta H=-395\,kJ\] C (graphite) \[+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}};\Delta H=-393\,kJ\] The heat of formation of diamond from graphite is

    A)  +2.0 kJ         

    B)  - 1.5 kJ

    C)  -788 kJ        

    D)  788 kJ

    Correct Answer: A

    Solution :

    C (diamond) \[+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}};\]      \[\Delta H=-395\,kJ\]                  ... (i) C (graphite) \[+{{O}_{2}}\xrightarrow{{}}{{O}_{2}};\]         \[\Delta H=-393\,kJ\]                  ... (ii) Eq. (i)-Eq. (ii), we get                 C (diamond) \[\xrightarrow{{}}C\] (graphite)                 \[\Delta H=[-395-(-393)]\,\,kJ=-2.0\,kJ\]and C (graphite) \[\xrightarrow{{}}C\] (diamond); \[\Delta H=+2.0\,kJ\]


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