A) H
B) \[{{H}^{+}}\]
C) \[{{H}^{-}}\]
D) \[2{{H}_{2}}\]
Correct Answer: C
Solution :
\[LiAl{{H}_{4}}\] is actually \[Li[Al({{H}_{4}})]\]. In it, the ligand present is hydride ion, \[i.e.\,,\,{{H}^{-}}\]
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