A) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}-C{{H}_{2}}I\]
B) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-\overset{\begin{smallmatrix} I \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,}}\,-H\]
C) \[C{{H}_{3}}C{{H}_{2}}CH-\overset{\begin{smallmatrix} I \\ | \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}Cl\]
D) \[C{{H}_{3}}C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{\overset{\begin{smallmatrix} I \\ | \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{3}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-C\equiv CH+HCl\xrightarrow{{}}\] \[C{{H}_{3}}C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}\xrightarrow{HI}\] \[C{{H}_{3}}-C{{H}_{2}}-\overset{\begin{smallmatrix} I \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{3}}\] 2-chloro- 2- iodobutane
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