A) \[\frac{v}{\sqrt{2}}\]
B) \[\frac{v}{2}\]
C) \[\frac{v}{3}\]
D) \[\frac{v}{4}\]
Correct Answer: C
Solution :
We have, \[v=\frac{v+{{v}_{s}}}{v-{{v}_{s}}}\] or \[2f=\frac{v+{{v}_{s}}}{v-{{v}_{s}}}f\] or \[2(v-{{v}_{s}})=v+{{v}_{s}}\] or \[2v-2{{v}_{s}}=v+{{v}_{s}}\] \[\therefore \] \[v=3{{v}_{s}}\] or \[{{v}_{s}}=\frac{v}{3}\]
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