BCECE Medical BCECE Medical Solved Papers-2013

  • question_answer
    In an electron microscope if the potential is increased from 20 kV to 80 kV, the resolving power R of the microscope will become

    A)  0

    B)  W

    C)  4R

    D)  5R

    Correct Answer: B

    Solution :

    Resolving power \[\propto \frac{1}{\lambda }\] and \[\propto \frac{1}{\sqrt{v}}\] \[\therefore \] \[R\,.\,P\propto \sqrt{v}\] \[\Rightarrow \] \[{{(R\,.\,\,P)}_{2}}={{(R\,.\,P)}_{1}}\times \sqrt{\frac{80kV}{20kV}}\] \[=2{{(R\,.\,P)}_{1}}\]


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