A) 2560 \[N/{{m}^{2}}\]
B) 3720 \[N/{{m}^{2}}\]
C) 1208 \[N/{{m}^{2}}\]
D) 950 \[N/{{m}^{2}}\]
Correct Answer: A
Solution :
\[p=\frac{4T}{R}=\frac{4\times 1.6}{2.5\times {{10}^{-3}}}\] \[=2560\,\,N/{{m}^{2}}\]
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